Finder
Veteran
It's no wonder this place struggles to attract actual photographers ... and the ones that do land here get bored pretty quickly and soon make a hasty exit.
Bloody scientists! 😀
(tongue in cheek)
Why cloud the issue with facts...
It's no wonder this place struggles to attract actual photographers ... and the ones that do land here get bored pretty quickly and soon make a hasty exit.
Bloody scientists! 😀
(tongue in cheek)
Look at the background and the size of the oof "blur" circles (behind her left ear).
Yes it is magnified. But that doesn’t mean that there is less in focus. :bang:
That one is so wrong that you don't even need to test it. The essential of DOF is that your eye cannot distingiush the size of the blur circle due to lack of resolution. And you are enlarging them.....
My hypothesis is that the DOF will be the same in 4x6, and 8x10 prints. Bu
.
Why cloud the issue with facts...
😕What has resolution of the sensor got to do with it??? The native COC of the sensor is 6.8 micron, so you are well over a meter wide at a guess then.
Yes - the resolution of your eye at the viewing distance. As soon as you cannot see the difference between an out-of-focus image point and a sharp image point due to your eye not being able to resolve it, your brain perceives both points as being equally sharp. That is the essential of DOF.
Now that we have established that, just for fun lets take a sensor which is the same size as the M8 sensor but increase the number of pixels it can produce by a factor of 1.33 linearly or whatever the sensor crop factor was. Now we take our picture and print it to the same size as before. The question is have we enlarged it as much as when we had less pixels? Relative to the sensor size we have but we have not spread the pixels so much.
Have a little think about what that means with regard to the theory that DOF is realtive to sensor size.
Look at the background and the size of the oof "blur" circles (behind her left ear).
That one is so wrong that you don't even need to test it. The essential of DOF is that your eye cannot distingiush the size of the blur circle due to lack of resolution. And you are enlarging them....
Roland, nicely put, but I am getting the feeling of Deja vu all over again.
I totally don't understand this.😕
Yes, 1/1000 as fastest shutter speed is too slow for our finer grained films, digital sensors, with apertures above f4 or 5.6 or so.
1K = 1/1000 ? I thought that was a fast shutter speed not slow.😕
If you are sincere, and want to know about diffraction, let me know, and I'll summarize the issues in a different thread.
Totally Ampguy.
If I am going to get diffraction problems with my digital cameras at stops greater (or smaller?) than f4, I want to know about it!
Let's not make premature assumptions, until we have the actual physical data in hand.
sorry - I fail to distill any meaning from this post. Could you please reformulate.So we need to base our calcultions on suiting the resolution of the eye. And to do that we need to create C0C of a certain size which gives us sufficient resolution on the print. So Resolution is actually fundamental to this DOF thing working.
Now that we have established that, just for fun lets take a sensor which is the same size as the M8 sensor but increase the number of pixels it can produce by a factor of 1.33 linearly or whatever the sensor crop factor was. Now we take our picture and print it to the same size as before. The question is have we enlarged it as much as when we had less pixels? Relative to the sensor size we have but we have not spread the pixels so much.
Have a little think about what that means with regard to the theory that DOF is realtive to sensor size.