foolproof
Established
Scratch the above. Had a play and it looks like to compensate you could just use a 2 stops up to roughly judge the correct zone. ie. f11 on the x100 in camera scale would actually show you what 5.6 would if scale were correct. Numbers closely match when using two dof calculator windows and the camera, with one dof cal set to x100 35mm and one to x100 23mm.
ie. dof cal - x100 35mm f5.6 - 5.86/8.68
camera - x100 camera f5.6 - 5.86/8.68 visual approximation
dof cal - x100 23 f2.8 - 5.71/9.04
Does that make sense theory wise at all for the more learned of us?
ie. dof cal - x100 35mm f5.6 - 5.86/8.68
camera - x100 camera f5.6 - 5.86/8.68 visual approximation
dof cal - x100 23 f2.8 - 5.71/9.04
Does that make sense theory wise at all for the more learned of us?
Last edited:
Spyro
Well-known
Further to the other X factors mentioned above (assumptions on CoC, print size, viewing distance, viewing eye), the lens design also plays a small role. Not all 23mm lenses are created exactly equal in terms of dof. Very similar but not identical.
Therefore agreed: the best way to get a good feel for the dof that your lens gives you is to use it. A lot. Use calcs/tables if needs be but only as a rough guidance.
Therefore agreed: the best way to get a good feel for the dof that your lens gives you is to use it. A lot. Use calcs/tables if needs be but only as a rough guidance.
Last edited:
I shoot nothing but fast lenses used wide-open so I can avoid all of these discussions.