New to 28mm, any tricks?

[Rob-F]

All of the above. And be careful metering slavishly with the red LEDs as the sky makes too big a contribution to the exposure with a 28.

Under those circumstances, I take an incident light reading as a check on my reflected reading.

 

[Joran]

Wow, thanks for all the reply's. Picked the Summicron up yesterday. What a great lens. I already own a 35mm Summicron V2. Amazing. I'll take it for a spin tomorrow in Amsterdam.

About the metering. I usually meter pointing slightly down, to my subjects to prevent underexposing.

 

[NeonKnight]

Pretty much use an equalateral triangle to remember framing using my distance to subject as matching my frame length.

Cal, I'm not following. Could you elaborate on this technique?

 

[aizan]

how far away you are from your subject is the width of what will be in the frame (at the subject's distance).

if you are 10 feet away from a person, imagine there's a 10 foot line going left to right under the person's, uh, feet.

 

[mod2001]

how far away you are from your subject is the width of what will be in the frame (at the subject's distance).

if you are 10 feet away from a person, imagine there's a 10 foot line going left to right under the person's, uh, feet.

The triangle works with a 35mm lens for FF, 28mm is wider, around 13 feet in your example 😉.

I'm always surprised about the huge difference between 28 and 35mm in regards to framing and composition. Big enough to grab quite often my F3 with the 28mm too and add it to my always with me Contax T3. Really sad, that the (Film) Ricoh GR is so prone to failure, would be the perfect companion.

Jürgen

 

[aizan]

i can't do math anymore! 😀

 

[mod2001]

i can't do math anymore! 😀

you can and for sure better than me 🙂, but the horizontal angle of view for the 28mm is 65,5º and not 60º 😉 I tried several websites with calculations now, all say around 12,9 feet with 28mm, and 10,3 with the 35mm(around 54.4°)

for example: https://www.pointsinfocus.com/tools/depth-of-field-and-equivalent-lens-calculator.

Jürgen

 

[Richard G]

i can't do math anymore! 😀

So the distance to the subject is the square root of 2 divided by 2, multiplied by the width of the frame; or ~0.7 times the width of the frame. I don’t know about the rest of you but I find this doesn’t really help me. Happy shooting with the 28.

 

[Doug]

you can and for sure better than me 🙂, but the horizontal angle of view for the 28mm is 65,5º and not 60º 😉 I tried several websites with calculations now, all say around 12,9 feet with 28mm, and 10,3 with the 35mm(around 54.4°)

for example: https://www.pointsinfocus.com/tools/depth-of-field-and-equivalent-lens-calculator.

Jürgen

But my info shows the Summicron 28mm v.1 has a 76° angle of view and the v.2 has 75°... Typo?

 

[shimokita]

a typical 28mm lens will have 65° - 46° - 75° angle of view depending if you are talking about width, height, or diagonal ; )

 

[mod2001]

a typical 28mm lens will have 65° - 46° - 75° angle of view depending if you are talking about width, height, or diagonal ; )

Exactly, and for the example mentioned above we have to use the value for width, means around 65°.

Jürgen

 

[robert blu]

Let's try to make it easier, we do not go out with a goniometer 🙂

You shoot horizontally with a 35mm lens and your subject is 12 feet from you: the longest side of your frame will be 12 feet.

With a 28 it will be a little more, let's say 15 more or less.

But the best way is "learn" a lens is to shoot, shoot snd than shoot again and evaluate results!

robert

 

[shimokita]

a typical 28mm lens will have 65° - 46° - 75° angle of view depending if you are talking about width, height, or diagonal ; )

__________

I have the 28mm f/2.8 Elmarit-M ASPH, the data sheet gives the following:

Angle view (diagonal, horizontal, vertical)

For 35 mm (24 x 36 mm): 75°/65°/46°

for M8 (18 x 27 mm): 60°/51°/36°
corresponds to a focal length of approx. 37 mm with 35 mm-format
__________

For the Summicron-M 28mm f/2 ASPH. the technical data sheet added "ca." to the angle of view and indicated (for vertical) 35° rather than 36° Summicron vs. Elmarit on an M8

Angle view (diagonal, horizontal, vertical)
For 35 mm (24 x 36 mm): ca. 74°/65°/46°;
for M8 (18 x 27 mm): 60°/51/35°
__________

Checking the M10 and Monochrom below is the sensor size:

M10: Sensor CMOS sensor, active surface area approx. 24 x 36mm

Monochrom: B/W CMOS chip, active area approx. 23.9 × 35.8 mm
(corresponds to usable format of analog Leica M models)
__________

nit-picking but it seems that the angle of view might be slightly different depending on a couple of factors (?) ...

.

 

[mark_pw]

Angle viewfinder?

Angle viewfinder?

I think an angle viewfinder can save you a few inches. 😎

 

[telenous]

If you shoot a M-body use the 90mm frames as the middle rectangle as in "the rule of thirds." this is very helpful in composition.

....

Very cool tip!