jano said:
Roger, your description of what happens was buried inside a long response to issues unrelated to my original question - that's why I just found it after you mentioned now, thanks for pointing it out. It does make some sense, but tough to understand without some sort of illustration. However, there are two issues:
1. have you had this lens as optimized at 2.8?
2. what happens to the focus point on a 1.5 optimized lens as it approach f4 versus the 2.8?
This is what I'm after. I'm not sure why that isn't clear -- quoting myself in the first post, "for those of you that have had the lens adjusted" -- sheesh.
This lens is factory optimized at f/1.5 (I picked it up at Oberkochen). I do not know if it is a conversion or original, but according to Zeiss,
there is no difference between a factory original and a conversion. If I understand correctly -- and I think I do -- it is merely a question of the angular position of the focusing cam: a new cam is not needed. This is why I said that if you're a foot out, I'd query either the adjustment or the camera rangefinder.
The test was focusing on a receding line of books. At f/1.5 the tiny amount of d-o-f (an inch/25mm or so, at the closest focus distance) is greater in front of the focused point than behind. At f/2.8 the d-o-f in front is about the same as at f/1.5, but the d-o-f behind is much greater. After that, d-o-f grows in both directions, but faster behind the focused point than in front.
In other words, the focused point recedes as you stop down, but the d-o-f grows (as usual) and by f/4 or f/5.6 it is enough that you don't need to worry, even at the closest focused point. I did not test at f/4 but at f/1.5, 2.8, 5.6 and 11.
With an f/2.8 optimization, the focused point is in front of the rangefinder focus; about an inch or two, I believe, though frankly, I didn't pay much attention bevause this is not a lens that most people will be using at full aperture at the closest focusing distance. At f/2.8 it is spot on. At f/4 to f/5.6, as before, it's not really an issue.
Does this answer your question?
Cheers,
R.