tlitody
Well-known
All the glass is being used regardless of the aperture, if you partially obscure the edge of a lens with say your finger, it will still be visible as the lens is stopped down. Try it with an SLR and you'll see.
Not all of the potential image forming forming light is being used when you close down. But the point is that for the same aperture on a MF 80 lens, say 5.6 verses a 135 camera lens of say 50mm at 5.6. The MF 80 Lens 5.6 has a much bigger physical aperture.
Lets use a simple example of a 40mm lens on a 135 camera at F4.0 and an 80mm lens on a MF camera at F4.0 cos the maths is simple.
F4 on the 80mm lens will be 4 times the physical aperture size on the 40mm lens at F4.0. But because the magnification of the 80mm lens is twice that of the 40mm lens, it will be spread over 4 times the area so the exposure is the same. But the 80mm lens is using a much bigger glass area for any point but not as bright because of magnification spread. I'm suggesting the quality of any single point in the negative is better because of that bigger glass area. Analagous to increased multi sampling in a scan.
I can't explain it in maths.
Its my theory and I'm sticking to it. 😀
The telescope example is a humungous format camera so its not the same as just making an aperture bigger. Making an aperture bigger requires a bigger glass area to cover it and the light gathering area is increased at the same time.